rDrama
/
rDrama
9
10
Fork 7
Code Issues Pull Requests Packages Releases Wiki Activity

make neko's inline emoji search for substrings like the normal search

pull/134/head
Aevann 2023-02-24 02:57:54 +02:00
parent a42729329f
commit 1175340d06
1 changed files with 1 additions and 39 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

40
files/assets/js/emoji_modal.js
View File

@ -120,44 +120,6 @@ const emojisSearchDictionary = {
this.dict.splice(target ,0,new EmoijsDictNode(tag, emojiName));
},
/**
* We find the name of each emojis that has a tag that starts with query.
*
* Basically I run a binary search to find a tag that starts with a query, then I look left and right
* for other tags tat start with the query. As the array is ordered this algo is sound.
* @param {String} tag
* @returns {Set}
*/
searchFor: function(query) {
query = query.toLowerCase()
if(this.dict.length === 0)
return new Set();
const result = new Set();
let low = 0;
let high = this.dict.length;
while (low < high) {
let mid = (low + high) >>> 1;
if (this.dict[mid].tag < query)
low = mid + 1;
else
high = mid;
}
let target = low;
for(let i = target; i >= 0 && this.dict[i].tag.startsWith(query); i--)
for(let j = 0; j < this.dict[i].emojiNames.length; j++)
result.add(this.dict[i].emojiNames[j]);
for(let i = target + 1; i < this.dict.length && this.dict[i].tag.startsWith(query); i++)
for(let j = 0; j < this.dict[i].emojiNames.length; j++)
result.add(this.dict[i].emojiNames[j]);
return result;
},
/**
* We also check for substrings! (sigh)
* @param {String} tag
@ -496,7 +458,7 @@ function update_speed_emoji_modal(event)
speed_carot_modal.style.top = modal_pos.y + box_coords.y + 14 + "px";
// Do the search (and do something with it)
populate_speed_emoji_modal(emojisSearchDictionary.searchFor(current_word.substr(1).replace(/#/g, "").replace(/!/g, "")), event.target);
populate_speed_emoji_modal(emojisSearchDictionary.completeSearch(current_word.substr(1).replace(/#/g, "").replace(/!/g, "")), event.target);
}
else {